3*x^2+1100*x+25000=0

Solution for 3*x^2+1100*x+25000=0 equation:

3x^2+1100x+25000=0

a = 3; b = 1100; c = +25000;
Δ = b2-4ac
Δ = 11002-4·3·25000
Δ = 910000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{910000}=\sqrt{10000*91}=\sqrt{10000}*\sqrt{91}=100\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1100)-100\sqrt{91}}{2*3}=\frac{-1100-100\sqrt{91}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1100)+100\sqrt{91}}{2*3}=\frac{-1100+100\sqrt{91}}{6}
$